Question

please solve this !
the digit in the tens place of a two-digit number is 3 less than the digit in its units place. Find the number i
the quotient obtained when the number is divided by the sum of its digits is 4.​

Answer 1

Answer:

36

Process:

Let x be the digit in unit's place.

By question, Number is

(x - 3)*10+x = 10x - 30 + x = 11x - 30

Now:

Sum of digits: x - 3 + x = 2x - 3

So, (11x - 30)/(2x - 3) = 4

or, 11x - 30 = 8x - 12

or, 11x - 8x = -12 + 30

or, 3x = 18

or, x = 6

Ultimately,

The number is 36.

Answer 2

Answer:

36

Step-by-step explanation:

Let be the number for the units place be =x

The digit in the tens place of a two - digit number is = (x-3) * 10+x=10x-30+x=11x-30

A/Q

Sum of digits :x-3+x=2x-3

=>(11x-30) (2x-3)=4

=>11x-30=8x-12

=>11x-8x=12-30

=>3x =18

=>x=18/3

=>x=6

So now we have to multiply with 6 so, the ans we get it as=6*6=36

The ans is =36