Question

please solve this three.....
class 10 trigonometry....
if don't know plzz.. don't answer.......,​

Answer 1

Step-by-step explanation:

1. sin60⁰ cos30⁰ + sin30⁰ cos60⁰

= sin60⁰ cos30⁰ + cos60⁰ sin30⁰

from Sin(A+B)= SinA.CosB + CosA.SinB

so= sin(60⁰+30⁰)

= sin90⁰

= 1 (put the value of sin90⁰)

3. cos 45⁰

sec30⁰+ cosec 30⁰

put their value

= 1/√2

(2/√3) + 2

= 1/√2

(2+2√3)/√3

= 1x√3

√2(2+2√3)

= √3

√2(2+2√3)

Mark as brilliant

thanks