Question

please solve this to find x​

Answer 1

Answer:

the value is x is 3

Step-by-step explanation:

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Answer 2

Question:

Solve to find x

(a) $\frac{x + 3}{1 - x} = \frac{-9}{x}$

Solution:

$\frac{x + 3}{1 - x} = \frac{-9}{x}$

$x(x + 3) = -9(1-x)$

$x^{2} + 3x = -9 + 9x$

$x^{2} + 3x -9x +9 = 0$

$x^{2} -6x +9 = 0$

Apply splitting the middle term

$x^{2} -3x -3x +9 = 0$

$x(x - 3) -3(x -3) = 0$

$(x-3)(x-3) = 0$

The quadratic equation formed has two roots which are same.

x - 3 = 0

x = 3

The value of x is 3