Question

please solve this to me..........maths class 10

Answer 1

Hey !!!

From LHS

1 + tan²A/1+ secA

=> 1 ( 1 + secA ) + tan²A
-------------------------------------
( 1 + secA )

=> 1 + secA + tan²A
-----------------------------
(1 + secA )

=> sec²A + secA •°• [1 + tan²A =sec²A ]
------------------------
secA - 1

secA ( secA + 1 )
------------------------ [ 1 + secA cancelled ]
(1 + secA )

=> secA

°•° secA = 1/cosA RHS prooved

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Hope it helps you !!!

@Rajukumar111

Answer 2

hope this answer is helpful