Question

Please solve this tommorrow is my maths exam, and I am having doubt in these two please solve it....​

Answer 1

I hope I will help you so much

Answer 2

Answer:

1.)

<BAC = <BDA (90° Given)

AC = BD (Given)

BC = BC (Given)

∆ ABC =~ ∆BDC (RHS)

2.)

In ∆ BCF and ∆ CBE :

BC = BC (Common)

FB = EC ( AB=AC and F and E are the mid points)

<FBC = <BCE (Given)

∆BCF =~ ∆CBE (SAS)

BE=CF (CPCT)