Math, asked by devsundarbanik, 1 month ago

Please solve this tommorrow is my maths exam, and I am having doubt in these two please solve it....​

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Answers

Answered by Komalshajeda
1

I hope I will help you so much

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Answered by vikashkumar888
1

Answer:

1.)

<BAC = <BDA (90° Given)

AC = BD (Given)

BC = BC (Given)

∆ ABC =~ ∆BDC (RHS)

2.)

In ∆ BCF and ∆ CBE :

BC = BC (Common)

FB = EC ( AB=AC and F and E are the mid points)

<FBC = <BCE (Given)

∆BCF =~ ∆CBE (SAS)

BE=CF (CPCT)

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