please solve this trignometic ques
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=sec 29/sec(90-61)+2cot8.cot17.cot45.cot73.cot82-3sin^2 38+sin^52)
=1+2cot8.cot17.1.tan(90-73).tan(90-82)-3(sin^2 38+cos ^2(90-52)
= 1+2cot8.cot17.tan17.tan8-3(sin^2 38+cos^38)
=1+2-3=0
Hope it helps you.
Answered by
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Answer:
Step-by-step explanation:
sec 29/sec(90-61)+2cot8.cot17.cot45.cot73.cot82-3sin^2 38+sin^52)
=1+2cot8.cot17.1.tan(90-73).tan(90-82)-3(sin^2 38+cos ^2(90-52)
= 1+2cot8.cot17.tan17.tan8-3(sin^2 38+cos^38)
=1+2-3=0
Hope it helps you.
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