please solve this Trigonometric question.
Correct answer will be brainliest
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1/sin 10° - root 3 / cos 10° = 4
(cos 10° - √3 sin 10°) / sin 10° cos 10°= 4
2(1/2 cos 10° - √3/2 sin 10°) / 1/2 * 2sin 10° cos 10°
1/2 = cos 60° and √3/2 = sin 60°
2(cos 60° cos 10° - sin 60° sin 10°) / 1/2 * 2sin 10° cos 10°
2 cos (60° + 10°) / 1/2 sin 20°
4 cos 70°/ sin 20°
4 cos 70° / sin (90° - 70°)
4 cos 70° / cos 70°
4 = 4
LHS = RHS
hence proved
(cos 10° - √3 sin 10°) / sin 10° cos 10°= 4
2(1/2 cos 10° - √3/2 sin 10°) / 1/2 * 2sin 10° cos 10°
1/2 = cos 60° and √3/2 = sin 60°
2(cos 60° cos 10° - sin 60° sin 10°) / 1/2 * 2sin 10° cos 10°
2 cos (60° + 10°) / 1/2 sin 20°
4 cos 70°/ sin 20°
4 cos 70° / sin (90° - 70°)
4 cos 70° / cos 70°
4 = 4
LHS = RHS
hence proved
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