Question

Please solve this two questions..
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Too urgent..
Correct answer will be marked as Brainlist + 15 thnx...
So please No Spam..

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Answer 1

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⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐

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1. since it is given that 3x=cosec theta and 3/x=cot theta

• so,x=cosec theta/3 & 1/x=cot theta/3

• so,3(cosec theta^2/9 - cot^2/9)

• 3[1/9(cosec theta^2 - cot theta^2). -(1)

• as we know that 1 + cot theta^2=cosec theta^2

• 1=cosec theta^2 - cot theta ^2. -(2)

• putting value of (2) in (1)

• 1/3(1)

• 1/3

• I would suggest u to first WRITE the given solution in copy as given for better clearance of your doubts and if not understood then type it.

2.okk so NexT is This...

• secA = 2x -----( 1 )

• tanA = 2/x ------( 2 )

• sec² A - tan² A = 1

• ( 2x )² - ( 2 /x )² = 1

• 4x² - 4/x² = 1

• 4 ( x² - 1/ x² ) = 1

• 2( x² - 1/ x² ) = 1/2

• I hope this helps you.

Mark Me...BRAINLEIST

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⭐⭐⭐ ALWAYS BE HAPPY ⭐⭐⭐

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Answer 2

Answer:

btt krle yr...pls... sunita pls