Math, asked by alphaak243gmailcom, 10 months ago

please solve this... urgent​

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Answered by itzkarina
2

Given:

(a/x - b) + (b/x - a) = 2

=> a(x - a) + b(x - b) = 2(x - a)(x - b)

=> ax - a² + bx - b² = 2(x² - bx - ax + ab)

=> ax - a² + bx - b² = 2x² - 2bx - 2ax + 2ab

=> ax - a² + bx - b² - 2x² + 2bx + 2ax - 2ab = 0

=> 2x² - 3(a + b)x + (a + b)² = 0

=> 2x² - 2(a + b)x - (a + b)x + (a + b)² = 0

=> 2x(x - (a + b)) - (a + b)(x - (a + b)) = 0

=> (2x - (a + b))(x - (a + b)) = 0

=> x = (a + b)/2 (or) x = a + b

Hope it help!

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