Question

Please solve this using differentiation by quotient rule.

Answer 1

First method:
_______________________________________
y= (secx- tanx)(secx+ tanx)
y= sec²x-tan²x
differentiate with respect to x,
dy/dx=2.secx.secx.tanx-2tanx.sec²x
dy/dx=2tanx.sec²x-2tanx.sec²x
dy/ dx= 0
_______________________________________
second method:
_______________________________________
we know that:
sec²x-tan²x=1
y= (secx-tanx)(secx+tanx)=(sec²x-tan²x)=1
y=1
differentiate with respect to x,
dy/dx= 0.
_______________________________________
please mark me brainliest
_______________________________________