Question

Please solve this using midpoint theorem

Answer 1

ABC is an equilateral triangle

In triangles BDF and CDF

BD=CD (D is the mid point)

AngleB =angle C (equilateral triangle)

BF=CE (F and E are the mid points of the equal sides of an equilateral triangle)

By SAS Triangle BDF Congruent to triangle CDF



In the same way proveTRIANGLE BDF and AEF

TRIANGLES BDF=CDF=AEF

by CPCT DE=EF=FD

hence DEF is an equilateral triangle