Question

Please solve this will mark as brainliest..

In the given figure PQRS is a rectangle and diagonals intersect at O.
If angle POQ=94°.
Find angle PQO and ANGLE PSO.​

Answer 1

Answer:

We have Diagonals of the rectangle (i.e AC and BD)

We know that the diagonals of rectangle divides each other in two equal parts. So, AO=BO=CO=DO

And AC = BD

Now in triangle POQ

PO=QO

So,Triangle POQ is an isoceles Triangle.

Therefore <P = <Q    (Angles opposite to the equal sides of isoceles triangle)

<P+<Q+<O=180     (Angle sum property of a triangle)

2<P+<O=180          (<P=<Q)

2<P=180-<O

2<P=180-94

2<P=86

<P=43

Therefore <PQO=43

Also, <PSO=43              (Alternate interior Angles)

Step-by-step explanation: