Question

please solve this.
will mark you as the brainliest​

Answer 1

Answer:

Hello 1 here is ur answer,

$\frac{5^{-3} *3^{3}*5^{3} }{3^{-2}*3^{8}*3^{2} }$ =  $\frac{3^{2} *3^{3}*5^{3} }{5^{3}*3^{8}*3^{2} }$

              $=(3)^{2+3-8-2} *5^{3-3} \\\\=3^{-5} * 5^{0} = \frac{1}{3^{5} } *1$

              $=\frac{1}{243} (or) 243^{-1}$