Question

please solve this with clear explanation​

Answer 1

Answer:

166. c) Co^+3, 4 unpaired electrons in the d-orbital

167. c) Fe^+2

Magnetic moment, m = $\sqrt{n(n + 2} )$ = 4.9, where, n is the no. of unpaired electrons

n(n+2) = 24

n^2 + 2n -24 = 0

By solving the equation with positive roots

n = 4

Among options, Fe^+2 have 4 unpaired electrons.

hope this will help you

Answer 2

Answer:

1. option d

2. don't know