Math, asked by palak5354, 11 months ago

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Answered by Anonymous
14

Ques - The sides of a triangle are 6.5cm, 7cm and 7.5 cm. A parallelogram, stands on side of length 7cm and has the same area as that of Triangle. Find the height of the parallelogram.

Solution - Sides of triangle = 6.5cm, 7cm and 7.5cm

Area of triangle can be found by Heron's formula

let a = 6.5cm

b = 7cm

c = 7.5cm

s = (a+b+c)/2

s = 6.5 + 7 + 7.5/2

s = 21/2 = 10.5cm

 \sqrt{s(s - a)(s - b)(s - c)}  \\  \\  \sqrt{10.5(10.5 - 6.5)(10.5 - 7)(10.5 - 7.5)}  \\  \\  \sqrt{10.5 \times 4 \times 3.5 \times 3}  \\  \\  \sqrt{441}  \\  \\  = 21cm {}^{2}

Area of triangle = 21 cm^2

Area of Parallelogram is also 21 cm^2

Area of triangle = Base × height = 21 cm^2

Given that Parallelogram stands on the side 7cm of triangle

So, base = 7cm

=> 7 × h = 21

h = 21/7

h = 3cm

Answered by shabaz1031
3

Answer:

HEY MATE HERE IS YOUR ANSWER...

Sides of triangle = 6.5cm, 7cm and 7.5cm

Sides of triangle = 6.5cm, 7cm and 7.5cmArea of triangle can be found by Heron's formula

Sides of triangle = 6.5cm, 7cm and 7.5cmArea of triangle can be found by Heron's formulalet a = 6.5cm

Sides of triangle = 6.5cm, 7cm and 7.5cmArea of triangle can be found by Heron's formulalet a = 6.5cmb = 7cm

Sides of triangle = 6.5cm, 7cm and 7.5cmArea of triangle can be found by Heron's formulalet a = 6.5cmb = 7cmc = 7.5cm

Sides of triangle = 6.5cm, 7cm and 7.5cmArea of triangle can be found by Heron's formulalet a = 6.5cmb = 7cmc = 7.5cms = (a+b+c)/2

Sides of triangle = 6.5cm, 7cm and 7.5cmArea of triangle can be found by Heron's formulalet a = 6.5cmb = 7cmc = 7.5cms = (a+b+c)/2s = 6.5 + 7 + 7.5/2

Sides of triangle = 6.5cm, 7cm and 7.5cmArea of triangle can be found by Heron's formulalet a = 6.5cmb = 7cmc = 7.5cms = (a+b+c)/2s = 6.5 + 7 + 7.5/2s = 21/2 = 10.5cm

Sides of triangle = 6.5cm, 7cm and 7.5cmArea of triangle can be found by Heron's formulalet a = 6.5cmb = 7cmc = 7.5cms = (a+b+c)/2s = 6.5 + 7 + 7.5/2s = 21/2 = 10.5cm\begin{lgathered}\sqrt{s(s - a)(s - b)(s - c)} \\ \\ \sqrt{10.5(10.5 - 6.5)(10.5 - 7)(10.5 - 7.5)} \\ \\ \sqrt{10.5 \times 4 \times 3.5 \times 3} \\ \\ \sqrt{441} \\ \\ = 21cm {}^{2}\end{,gathered}

} s(s−a)(s−b)(s−c)

} s(s−a)(s−b)(s−c)

} s(s−a)(s−b)(s−c)

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5)

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5)

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5)

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441 =21cm

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441 =21cm 2

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441 =21cm 2

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441 =21cm 2

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441 =21cm 2 Area of triangle = 21

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441 =21cm 2 Area of triangle = 21Area of Parallelogram is also 21

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441 =21cm 2 Area of triangle = 21Area of Parallelogram is also 21Area of triangle = Base × height = 21 cm^2

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441 =21cm 2 Area of triangle = 21Area of Parallelogram is also 21Area of triangle = Base × height = 21 cm^2Given that Parallelogram stands on the side 7cm of triangle

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441 =21cm 2 Area of triangle = 21Area of Parallelogram is also 21Area of triangle = Base × height = 21 cm^2Given that Parallelogram stands on the side 7cm of triangleSo, base = 7cm

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441 =21cm 2 Area of triangle = 21Area of Parallelogram is also 21Area of triangle = Base × height = 21 cm^2Given that Parallelogram stands on the side 7cm of triangleSo, base = 7cm=> 7 × h = 21

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441 =21cm 2 Area of triangle = 21Area of Parallelogram is also 21Area of triangle = Base × height = 21 cm^2Given that Parallelogram stands on the side 7cm of triangleSo, base = 7cm=> 7 × h = 21h = 21/7

} s(s−a)(s−b)(s−c) 10.5(10.5−6.5)(10.5−7)(10.5−7.5) 10.5×4×3.5×3 441 =21cm 2 Area of triangle = 21Area of Parallelogram is also 21Area of triangle = Base × height = 21 cm^2Given that Parallelogram stands on the side 7cm of triangleSo, base = 7cm=> 7 × h = 21h = 21/7h = 3cm

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