Question

please solve this with complete solution...need urgently.... please​

Answer 1

Answer:

Put the value of DE because it is not visible in the photo to get the answer.

Answer 2

In triangle, ABH

AH = 5cm

BH = 12cm

Area of triangle ABH = 1/2×base×height

Base = BH = 12cm , height = AH = 5cm

Area = 1/2×12×5

6×5 = 30 cm^2

In triangle FEI

FI = 5cm = height

IE = 16cm = base

Area = 1/2×16×5

8 × 5 = 40cm^2

In triangle BCG

Area = 1/2×BG×GC

1/2×4×3

6cm^2

In triangle JED

By Pythagoras theorem -

(JE)^2 + (JD)^2 = (DE)^2

5^2 + 3^2 = (DE)^2

25 + 9 = (DE)^2

34 = (DE)^2

√34 = DE

5.8cm = DE

Area = 1/2×5.8×3

8.7 cm^2

Cost of developing garden in triangle ABH ->

Cost of 1 cm^2 = ₹100

Cost of 30cm^2 = 100×30 = ₹3000

In triangle FEI

Cost = 40×100 = ₹4000

In triangle BCG

Cost = 6×100 = ₹600

In triangle JED

Cost = 100×8.7 = ₹870