Question

Please solve this with full solution

Answer 1

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→ Given that the rate constant for a first order reaction is $60\: {s}^{-1}$ .

→ Let $a$ M be the initial concentration.

→ First initial concentration be $\frac{a}{16} M$

→ Rate concentration ,

$k = 60/s$

$t = \frac{2.303}{k} \: log \: ( \frac{A o}{A} ) \\ \\ t = \frac{2.303}{60} \: log \: ( \frac{a}{ \frac{a}{16} } ) \\ \\ t = 4.6 \times {10}^{ - 2} seconds$

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