Question

please solve this

with full solution​

Answer 1

ʟᴇᴛ ᴛʜᴇ ǫᴜᴀʟɪᴛʏ ᴏғ ᴍɪʟᴋ ɪɴ 60L ᴏғ ᴍɪxᴛᴜʀᴇ = X

ᴀɴᴅ ᴛʜᴇ ᴀᴍᴏᴜɴᴛ ᴏғ ᴡᴀᴛᴇʀ ɪɴ 60ʟ ᴏғ ᴍɪxᴛᴜʀᴇ =(60-x) ʟ

ᴛʜᴇɴ

$\frac{x}{60 - x} = \frac{2}{1}$

ʙʏ ᴄʀᴏss ᴍᴜʟᴛɪᴘʟʏ ᴍᴇᴛʜᴏᴅ

=2 ( 60 - x ) = x

= 120 - 2x = x

= 120 = x + 2x

= 120 = 3x

= 120/3 = x

= x = 40

ᴍɪʟᴋ ɪɴ ᴍɪxᴛᴜʀᴇ = 40ʟ

ᴀɴᴅ ᴡᴀᴛᴇʀ ɪɴ ᴍɪxᴛᴜʀᴇ = 60 - 40 = 20 ʟ

ɴᴏᴡ ʟᴇᴛ ʏ ʟɪᴛᴇʀs ᴏғ ᴡᴀᴛᴇʀ ᴛᴏ ʙᴇ ғᴜʀᴛʜᴇʀ ᴀᴅᴅᴇᴅ

sᴏ ,

$\frac{milk}{water} = \frac{40}{20 + y} = \frac{1}{2}$

ʙʏ ᴄʀᴏss ᴍᴜʟᴛɪᴘʟʏ ᴍᴇᴛʜᴏᴅ

40 × 2 = 20 + ʏ

80 = 20 + ʏ

80 - 20 = ʏ

60 = ʏ

60 ʟɪᴛᴇʀs ᴏғ ᴡᴀᴛᴇʀ ᴛᴏ ʙᴇ ғᴜʀᴛʜᴇʀ ᴀᴅᴅᴇᴅ

Answer 2

Let the quantity of milk in 60l of mixture = x

And amount of water in 60l of mixture = (60-x)

$then \: = \frac{x}{60 - x} = \frac{2}{1}$

By Cross multiply method

2(60 –x) = x

120 -2x = x

120 = x + 2x

120 =3x

120/3 = x

40 = x

or x = 40

Milk in mixture = 40 L

And water in mixture = 60 – 40

= 20 L

Now, let y litres of water to be further added

$so \frac{milk}{water} = \frac{1}{2}$

$\frac{40}{20 + y} = \frac{1}{2}$

By cross multiply method

40×2 = 20 +y

80 = 20 +y

80 -20 = y

60 = y

Or y =60

60 litres of water to be further added.