please solve this with procedure
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tan theta= ( m1- m2)/ (1+ m1m2)
= 1-1/√3)/ ( 1+ 1/√3
= √3 -1)/√3+1
= 1- √3
= 1-1/√3)/ ( 1+ 1/√3
= √3 -1)/√3+1
= 1- √3
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