please solve this with steps
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Two angles of quadrilateral Always equal to 180° so,
one angle is 165° then other is equal to
165-x=180°
X=180°-165°
X=15°
one angle is 165° then other is equal to
165-x=180°
X=180°-165°
X=15°
Answered by
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sum of all angles of a quadrilateral = 360'
so sum of nth term = 360
n = 4
sn = n/2(a+l)
360' = 4/2(a+165') (l = 165')
a+165' = 180'
a = 15'
a= 15 , an = 165
165 = 15 + 3d
3d = 150
d = 50
angles = a , a+d , a+2d , a+3d
= 15 , 15+50 , 15+100 , 15+150
= 15 , 65 , 115 , 165.
so sum of nth term = 360
n = 4
sn = n/2(a+l)
360' = 4/2(a+165') (l = 165')
a+165' = 180'
a = 15'
a= 15 , an = 165
165 = 15 + 3d
3d = 150
d = 50
angles = a , a+d , a+2d , a+3d
= 15 , 15+50 , 15+100 , 15+150
= 15 , 65 , 115 , 165.
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