Question

please solve this with steps​

Answer 1

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Answer 2

Answer:

Answer :-

given

$x + \frac{1}{x} = 3 \\ to \: find \: the \: value \: of \: {x}^{2} + \frac{1}{ {x}^{2} } ^{2} \\ we \: will \: do \: squaring \: on \: both \: side \\ ( x + \frac{1}{x} ) ^{2} = {3}^{2} \\ = > {x}^{2} + \frac{1 ^{2} }{ {x}^{2} } + 2 \times x \times \frac{1}{x} = 9 \\ = > {x}^{2} + \frac{1}{ {x}^{2} } = 9 - 2 \\ = > {x}^{2} + \frac{1}{ {x}^{2} } = 7$

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