Question

please solve this with steps​

Answer 1

I think this is the answer

Answer 2

47C4 + 51C3 + 50C3 + 49C3 + 48C3 + 47C3

As nCr + nC(r-1) = n+1)Cr

47C4 + 47C3 + 48C3 + 49C3 + 50C3 + 51C3

47C4 + 47C3 = 48C4

So 48C4 + 48C3 + 49C3 + 50C3 + 51C3

48C4 + 48C3 = 49C4

So 49C4 + 49C3 + 50C3 + 51C3

49C4 + 49C3 = 50C4

So 50C4 + 50C3 + 51C3

50C4 + 50C3 = 51C4

So 51C4 + 51C3 = 52C4

So its 52C4