Question

Please solve this x²-2ax-(4b²-a²)=0

Answer 1

hi
x²-2ax-(4b²-a²)= 0
x²-2ax = 4b²-a²
x(x-2a)= (2b)²-(a)²
x(x-2a) = (2b-a)(2b+a)

Answer 2

Step-by-step explanation:

USING QUADRATIC FORMULA, DISCRIMINANT

D = b²-4ac

=(-2a)² - 4×(-4b²+a²)×1

=4a² + 16b²-4a²

= 16b²

X = [-b+-(√D)]/4a

= [2a +- (√16b²)]/2

= [2a+- (4b)]/2

= a+- 2b