Question

Please solve this x2-2ax+(a2-b2)=0 by completing the square method

Answer 1

Answer:

Please solve this x2-2ax+(a2-b2)=0

SOLUTION : Given :

x² - 2ax + (a² - b²) = 0. (x² - 2ax + a²) - (b²) = 0. ...

[(a)² - 2ab + (b)² = (a - b)²] (x - a - b) (x - a + b) = 0.

[ a² - b² = (a - b)(a + b)] x - a - b = 0 or x - a + b = 0.

x = a + b or x = a - b.

Hence, the value of x is (a +b) or (a-b) HOPE THIS WILL HELP YOU…

Answer 2

Step-by-step explanation:

SOLUTION :

Given :

x² - 2ax + (a² - b²) = 0

(x² - 2ax + a²) - (b²) = 0

(x)² - 2a×x + (a)² - b²

(x - a)² - (b)² = 0

[(a)² - 2ab + (b)² = (a - b)²]

(x - a - b) (x - a + b) = 0

[ a² - b² = (a - b)(a + b)]

x - a - b = 0 or x - a + b = 0

x = a + b or x = a - b

Hence, the value of x is (a +b) or (a-b)

HOPE THIS WILL HELP YOU…