Math, asked by kolphira, 5 months ago

Please solve tis problem.​

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Answers

Answered by kashwini77
2

Step-by-step explanation:

hope it helps you

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Answered by Terachehra
10

Answer:

5^n*25^(n-1)÷{5^(n-1)*25^(n-1)}

5^n*5^2 (n-1)÷{5^(n-1)*5^2 (n-1)}

5^n*5^(2n-2)÷{5^(n-1)*5^(2n-2)}

5^(n+2n-2)÷{5^(n-1+2n-2)}

5^(3n-2)÷5^(3n-3)

5^(3n-2)/5^(3n-3)

5^(3n-2-3n+3)

5^1

5 ans..

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