please solve (v) question.....
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Let the age of Jacob after 5 year be a
Jacob's father's age after 5 year = 3a
Five years ago,
Jacob's age = (a - 10) year
Jacob's father's age = (3a - 10) year
According to question,
3a - 10 = 7(a-10)
=> 3a - 10 = 7a - 70
=> - 10 + 70 = 7a - 3a
=> 4a = 60
=> a = 15
Jacob's present age = a - 5
= 15 - 5
= 10 year
Jacob's father's present age = 3a - 5
= 45 - 5
= 40 year
Jacob's father's age after 5 year = 3a
Five years ago,
Jacob's age = (a - 10) year
Jacob's father's age = (3a - 10) year
According to question,
3a - 10 = 7(a-10)
=> 3a - 10 = 7a - 70
=> - 10 + 70 = 7a - 3a
=> 4a = 60
=> a = 15
Jacob's present age = a - 5
= 15 - 5
= 10 year
Jacob's father's present age = 3a - 5
= 45 - 5
= 40 year
Sanghamitra25:
i asked about subdivision ( v )..... not about subdivision ( vi )...
Answered by
1
Let the fraction be x/y
(x+2)/(y+2) = 9/11
(x+2)*11 = (y+2)*9
11x+22 = 9y+18
11x-9y = 18-22
11x-9y = -4 ....(i)
(x+3)/(y+3) = 5/6
(x+3)*6 = (y+3)*5
6x+18 = 5y+15
6x-5y =15-18
6x-5y = -3 ....(ii)
(11x-9y = -4)*5 ....(i)
(6x-5y = -3)*9 ....(ii)
Subtracting (ii) from (i)
55x-45y = -20
54x-45y = -27
(-) (+) (+)
x = 7
Substituting x in (i),
11x-9y = -4
11*7-9y = -4
77-9y = -4
-9y = -4-77
y = -81/-9
y = 9
Therefore, x=7 and y=9
:)
(x+2)/(y+2) = 9/11
(x+2)*11 = (y+2)*9
11x+22 = 9y+18
11x-9y = 18-22
11x-9y = -4 ....(i)
(x+3)/(y+3) = 5/6
(x+3)*6 = (y+3)*5
6x+18 = 5y+15
6x-5y =15-18
6x-5y = -3 ....(ii)
(11x-9y = -4)*5 ....(i)
(6x-5y = -3)*9 ....(ii)
Subtracting (ii) from (i)
55x-45y = -20
54x-45y = -27
(-) (+) (+)
x = 7
Substituting x in (i),
11x-9y = -4
11*7-9y = -4
77-9y = -4
-9y = -4-77
y = -81/-9
y = 9
Therefore, x=7 and y=9
:)
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