Math, asked by priyanshu2764, 1 year ago

please solve. very urgent

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Answered by MOSFET01
1
(5a²+3a-1) = (2a-5+7a²)+(3a²+4-a) + X

5a²+3a-1=10a²+a-1+X

5a²+3a-1-(10a²+a+1)=X

5a²+3a-1-10a²-a-1=X

-5a²+2a+0=X

2a-5a²=X

priyanshu2764: first line me 2 nahi 2a hai
priyanshu2764: please solve
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