please solve with correct method.....
rakeshmohata:
answer is 1
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Answered by
1
Hope u like my process
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Formula to be used
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
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
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Hope this is ur required answer
Proud to help you
=====================
Formula to be used
=-=-=-=-=-=-=-=-=-=-=-
_______________________
_______________________
Hope this is ur required answer
Proud to help you
Answered by
0
hey , 16 can be written as 2^4 where 4 will come front and log 2 base 2 is 1 and again 4 can be written as 2^2 and again 2 will come front and log 2 base 2 will be 1 and one will be left that is log 2 base 2 , again it will be 1 and therefore final answer will be 1
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