please solve with diagram.
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In triangleABC
angleB=90°
therefore it's a right angled triangle.
so AC is the hypotenuse.
AC^2=AB^2+BC^2
AC=√AB^2+BC^2
AC=√64+36
AC=√100
AC=10
As BD is the median so
BD=1/2×AC
=1/2×10
So BD=5
angleB=90°
therefore it's a right angled triangle.
so AC is the hypotenuse.
AC^2=AB^2+BC^2
AC=√AB^2+BC^2
AC=√64+36
AC=√100
AC=10
As BD is the median so
BD=1/2×AC
=1/2×10
So BD=5
Answered by
0
Answer:
In triangleABC angleB=90*
therefore it's a right angled triangle.
so AC is the hypotenuse. AC^2-AB^2+BC^2
AC-VAB^2+BC^2
AC=√64+36
AC=√100
AC=10
As BD is the median so
BD=1/2 AC
= 1/2*10
So BD=5
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