Math, asked by yuvrajsinghaulakh200, 25 days ago

Please solve with explanation​

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Answered by ankitkhatri944
0

Step-by-step explanation:

CAE=EAB

CBE=EBD

In triangle AEB,

EAB+AEB=EBD

AEB=EBD-EAB

In triangle ACB,

ACB+CAB=CBD

ACB+CAE+EAB=CBE+EBD

ACB+EAB+EAB=EBD+EBD

ACB+2EAB=2EBD

2EAB-2EBD=-ACB

2(EAB-EBD)=-ACB

2(-AEB)=-ACB

-AEB=-1/2ACB

AEB=1/2ACB

!!Hence Proved!!

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