please solve with explanation.
Attachments:
dityashahni:
3 s1 mai electron to easily niklega n
lagta h.. यह दोनों time pass kar rahe h!!
Haa.. but 2nd electron easily नहीं निकलेगा..
bcoz after removal of 1 electron it behaves as a noble gas.. and thus resist to give that electron
so energy more than difference is more
am i right??
yeah.. thus the gap is much higher between 1st and 2nd IP than in 2nd and 3rd IP in 3s¹
but according to question the gap is huge between 2nd and 3rd.
ok now I got it
hmm
Answers
Answered by
8
Hope u like my process
======================
© Is the answer
___________________
Reason:-
=-=-=-=-=-=
=> The difference between any two IP's is much more when the configuration behaves as noble gas.
=> In option a(❌) ,
The configuration is already a noble gas configuration so it's IP is much higher than the gap between 2nd and 3rd IP
=> In option b(❌) ,
After the removal of 1st electron, it attains the noble gas configuration... So, the difference between 1st and 2nd IP is much higher than 2nd and 3rd IP.
=> In option c(✔️) ,
After the removal of 2 electrons, it attains the noble gas configuration... So, the difference between 2nd and 3rd IP is much higher than 1st and 2nd..
The required terms as per given ⬆️
=> In option d(❌) ,
After removal of 1 electron, the s orbital is fully filled and thus the difference in 1st and 2nd IP is higher than 2nd and 3rd IP.
__________________________
Hope I explained u clearly.
Proud to help you
======================
© Is the answer
___________________
Reason:-
=-=-=-=-=-=
=> The difference between any two IP's is much more when the configuration behaves as noble gas.
=> In option a(❌) ,
The configuration is already a noble gas configuration so it's IP is much higher than the gap between 2nd and 3rd IP
=> In option b(❌) ,
After the removal of 1st electron, it attains the noble gas configuration... So, the difference between 1st and 2nd IP is much higher than 2nd and 3rd IP.
=> In option c(✔️) ,
After the removal of 2 electrons, it attains the noble gas configuration... So, the difference between 2nd and 3rd IP is much higher than 1st and 2nd..
The required terms as per given ⬆️
=> In option d(❌) ,
After removal of 1 electron, the s orbital is fully filled and thus the difference in 1st and 2nd IP is higher than 2nd and 3rd IP.
__________________________
Hope I explained u clearly.
Proud to help you
same here
good night
sweet dreams.......
same to u dear!! ❤️♥️❤️
being tired and bored.. have a entertaining dream.. that u can enjoy in night
thanks for that...
thanks for the brainliest one
Answered by
0
Answer:
the answer is d
Explanation:
Similar questions