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L = 80 cal/gm
m = 1 kg = 1000 gm
T = 273 K
Heat absorbed in change of phase Q = mL
ΔQ = 1000×80 = 8×10^4 cal.
S = ΔQ/T
= 8×10^4 /273
= 293 cal/K
i hope it will help you
regards
m = 1 kg = 1000 gm
T = 273 K
Heat absorbed in change of phase Q = mL
ΔQ = 1000×80 = 8×10^4 cal.
S = ΔQ/T
= 8×10^4 /273
= 293 cal/K
i hope it will help you
regards
cooldude06:
atb
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