Question

please solve with process

Answer 1

we know,

from equation of motion

S = uT + 1/2 @T²...........(1)

where, @= acceleration and T = time


Now, given

displacement along x axis = u(t-2s) + a(t-2s)².

Comparing with equation (1),

we get

u = u.

time(T) = t-2s.

and1/2@ = a.

thus,
@ = 2a.


Thus,acceleration of the particle will be 2a.
Ans.

Thanks

KSHITIJ