Question

please solve with solution ​

Answer 1

Answer:

Correct option is-3)

ſª₁ f(x)dx = 4 and ſ₂₁ [3 − f(x)dx = 7] F (4) - F(-1) → (1) = 4

and 3|x2 [F (4) — F (2)] = 7

[F (4) F (2)] = 6-7=−1 .. F (4) - F (2) = −1→ (2)

ſ²₁ f(x)dx =F (2) − F (−1)→ (3)

eqn. (1)-eqn. (2), we get F (2) – F(-1)=5 .:. S²₁ f(x)dx = [5] (put value in eqn.(3))