Question

Please solve with step by step by step solution

Answer 1

Answer:

Step-by-step explanation:

We have,

$\rm{x-\dfrac{2x+8}{3}=\dfrac{1}{4}\left\{x-\dfrac{2-x}{6}\right\}-3}$

$\rm{\implies\dfrac{3x-2x-8}{3}=\dfrac{1}{4}\left\{\dfrac{6x-2+x}{6}\right\}-3}$

$\rm{\implies\dfrac{x-8}{3}=\dfrac{1}{4}\left\{\dfrac{7x-2}{6}\right\}-3}$

$\rm{\implies\dfrac{x-8}{3}=\dfrac{7x-2}{24}-3}$

$\rm{\implies\dfrac{x-8}{3}=\dfrac{7x-2-72}{24}}$

$\rm{\implies\dfrac{x-8}{3}=\dfrac{7x-74}{24}}$

$\rm{\implies\,x-8=\dfrac{7x-74}{8}}$

$\rm{\implies\,8x-64=7x-74}$

$\rm{\implies\,8x-7x=64-74}$

$\rm{\implies\,x=-10}$