please solve with steps
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Sin(65°) = Sin(90° - 25°)
As Sin(90° - θ) = Cos(θ)
⇒ Sin(65°) = Cos(25°)
⇒ Sin²(65°) = Cos²(25°)
As Sin²(θ) + Cos²(θ) = 1
⇒ Sin²(25°) + Sin²(65°) = Sin²(25°) + Cos²(25°) = 1
Tan(5°) = Tan(90° - 85°)
As Tan(90° - θ) = Cot(θ)
⇒ Tan(5°) = Cot(85°)
Tan(15°) = Tan(90° - 75°)
⇒ Tan(15°) = Cot(75°)
As Tanθ × Cotθ = 1
⇒ Tan(5°) × Tan(85°) = Cot(85°) × Tan(85°) = 1
⇒ Tan(15°) × Tan(75°) = Cot(75°) × Tan(75°) = 1
As Tan(30°) = 1/√3
Substituting all the Values :
The Value of Question = 1 + √3(1/√3) = 1 + 1 = 2
rohit710:
Nice answer
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