Please solve: (x^2-1)(x-3)(x-5)+16
Answers
Answered by
0
Answer:This Is The Answer
Attachments:
Answered by
0
Answer:
(x2-x)(x-3)(x-5)+16
=x3+x3+3+5+16
=2x3+24
Now solving for x, 2x3+24=0
2x3= -24
x3= -24/2
x3= -12
x= -12cube root
Similar questions