Math, asked by edfcvbj, 9 months ago

Please solve: (x^2-1)(x-3)(x-5)+16

Answers

Answered by Anonymous
0

Answer:This Is The Answer

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Answered by AnshKumarGupta123
0

Answer:

(x2-x)(x-3)(x-5)+16

=x3+x3+3+5+16

=2x3+24

Now solving for x, 2x3+24=0

2x3= -24

x3= -24/2

x3= -12

x= -12cube root

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