Question

Please solve x^6-7x^3-8

Answer 1

x^ 6- 7x³-8 =0

let us assume y= x³
now above equation becomes

y²-7y-8=0

y²- 8y+y -8=0

y(y-8) +1(y-8) =0

( y+1)(y-8) =0

we can say that (x³+1)(x³-8) =0

(x³-8) =0. | (x³+1) =0
x³= 8. | x³= -1
x= 2. | x = -1

x have two values either -1 or 2

Answer 2

i hope this will usful to u