Question

Please solve x square +y square =3xy then show that 2 log (x+y) =log5+logx+logy​

Answer 1

Step-by-step explanation:

If x^2+y^2=3xy then prove that 2log( x-y)=logx-logy. 1 ... HEY WAKE UP AND PLEASE HELP ME WITH THIS PROBLEM! ... The solution of 5loga x + 5 xlog a5 = 3 (a > 0), is(c) 2- log 5 a5(a) 2loga 5(b) ...

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Answer 2

$Given \:- x² + y² = 3xy$ -----(1)

$We \: know \: that -$

$(x + y)² = x² + y² + 2xy$

$(x + y)² = 3xy + 2xy$

$(x + y)² = 5xy$

$Taking \: log \: both \: side$

$log(x + y)² = log(5xy)$

$We \: know \: that -$

$log(xyz) = logx + logy + logz$

$So ,$

$2log(x + y) = log5 + logx + logy$

$I \: hope \: that \: it \: will \: be \: helpful \: for \: u$