Question

please solved guys

tumhara dost ko Jaruret hai​

Answer 1

Step-by-step explanation:

Answer 1 :-

Let's assume that 0.33... be x.

x = 0.33 . . . ------(1)

Multiply by 10

10x = 3.33 . . . -----(2)

Subtract equation (1) from (2)

10x - x = 3.333 . . . - 0.333...

9x = 3

x = 1/3

Hence 0.333... is expressed in the form of p/q.

Answer 2 :-

Solving this question also by above method

Let's assume 1.27 27 27 . . . be y

y = 1.2727. . . ---(3)

multiply by 100

100 y = 127. 2727 . . . ---(4)

Subtract equation (4) from (3)

100y - y = 127.2727... - 1.2727...

99 y = 126

y = 126/99

Hence 1.272727.. is expressed as 126/99 in form of p/q