Please solvethe question no 9
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ans of the first part..
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MukeshPathakrockstar:
And second part
that part I want
i m trying wait plz
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1
1.diameter=4.2m.
therefore radius(r)=2.1m.
height(h)=4.5m
C.S.A of a cylinder=2(pi)(r)(h).
=2(22/7)(2.1)(4.5)
=59.4m2.
2.T.S.A=2(pi)(r)(h+r)
=2(22/7)(2.1)(4.5+2.1)
=13.2(6.6).
=87.12m2.
_________________________
2.Steel used:
Total surface area of the closed cylindrical petrol storage tank
= 2πr (r + h)
= 2×22/7 ×6.6
= 87.12 cm^2
Area of steel sheet wasted in making the tank
= 1/12 × total surface area
= 1/12 × 87.12
7.26
Actual area of the sheet used for making the tank.
= Total surface of the tank + Area of steel sheet wasted in making the tank
= 87.12 m2 + 7.26 m2
= 94.38 m2
therefore radius(r)=2.1m.
height(h)=4.5m
C.S.A of a cylinder=2(pi)(r)(h).
=2(22/7)(2.1)(4.5)
=59.4m2.
2.T.S.A=2(pi)(r)(h+r)
=2(22/7)(2.1)(4.5+2.1)
=13.2(6.6).
=87.12m2.
_________________________
2.Steel used:
Total surface area of the closed cylindrical petrol storage tank
= 2πr (r + h)
= 2×22/7 ×6.6
= 87.12 cm^2
Area of steel sheet wasted in making the tank
= 1/12 × total surface area
= 1/12 × 87.12
7.26
Actual area of the sheet used for making the tank.
= Total surface of the tank + Area of steel sheet wasted in making the tank
= 87.12 m2 + 7.26 m2
= 94.38 m2
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is 5.1975 the ans.?
No
95.04
ooo is it sured correct answer?
Ya
ok
R u satisfied
With the answee
Answer
ya now i understood thanxxx
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