Question

Please somebody help me solve this.​

Answer 1

Explanation:

C + 2Cl2 -----> CCl4

1 mole C = 2 mole Cl2

12g C = 2 X (35.5 X 2)g Cl2

12g C = 2 X (71)g Cl2

1g C = 2 X 71/ 12g (Cl2)

36g C = 2 X 71 /12 X 30 = 426g (Cl2)

1 mole Cl2 = 1 mole CCl4

(2) X (35.5 X 2) = (12 + 4 X 35.5)

142gm Cl2 = 154gm CCl4

142gm Cl2 = 154/142

= 154/142 X 142 = 154gm CCl4

Mass of Carbon left = (32 - 12)

2 mole Cl2 = 1 mole C

2 X (35.5 X 2) gm Cl2 = 12gm C

1 gm Cl2 = 12/142 g C

142gm Cl2 = 12/142 X 142

= 12g C

Mass of Cl2 remaining = 0