Question

please somebody solve any one of 5th question and 6th question

Answer 1

Given AD is the median of ΔABC and E is the midpoint of AD

Through D, draw DG || BF

In ΔADG, E is the midpoint of AD and EF || DG

By converse of midpoint theorem we have

F is midpoint of AG and AF = FG   → (1)

Similarly, in ΔBCF  

D is the midpoint of BC and DG || BF    

G is midpoint of CF and FG = GC → (2)

From equations (1) and (2), we get

AF = FG = GC → (3)

From the figure we have, AF + FG + GC = AC

AF + AF + AF = AC [from (3)]

3 AF = AC

AF = (1/3) AC

SOURCE-

https://www.nextgurukul.in/nganswers/ask-question/answer/AD-is-a-median-of-triangle-ABC-and-E-is-the-midpoint-of-AD/Quadrilaterals/29035.htm

Answer 2

Answer:

ur answer is given above please mark that answer as brainlist

hope that helps u