Question

please someone answer......

An electric bulb is rated 220V and 100W. when it is operated on 110 V, the power consumed will be:

just tell me what is the mistake the above solution.

correct ans: 25W
​

Answer 1

The power dissipated by an electric bulb is given as P = VI.

In this case, Power P = 100 W and Voltage V = 220 V.

So, current I is I = P/V = 100/220 = 0.45 A.

When the supplied voltage is 110 V, the power consumed will be P=VI = 110 * 0.45 = 50 W.

Hence, the power consumed when operated at 110 V is 50 W.

Answer 2

Explanation:

P = V^2/R If V = 220 V we have 100 W = 220^2/R R = 220^2/100 Ω = 484 Ω. This is the resistance of the bulb. When V = 110 V, power consumed = V^2/R = 110^2/484 = 25 W. So, 25 W power is consumed when it is operated on 110 V.

hope it helps

maeky me as brainlist