Question

please someone answer fast​

Answer 1

Answer:

√2x+√3y=0.......(1)

√3x-√8y=0.......(2)

from(1) x=-√3y/√2, put it in eq (2)

√3(-√3/√2)-√8y=0

-3y/√2 -√8y=0

take LCM of √2

-√3y-√16=0

-√3y-4=0

y=-4/√3

put it in eq(1)

√2x+√3(-4/√3)=0

√2x-4=0

x=4/√2

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