please someone answer this one quickly
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The answer should be 1st.
Aakashshrama:
no its the third one i also thought it ti be first
okay
Answered by
1
The above pic is about case-1
i.e the max force required to push the upper block so that the both the blocks move together.
Now,
case-2
If the upper block is pulled the lower block is accelerated by the frictional force between the blocks. The acceleration of the lower block is
a1=f/m1 (f is frictional force)
The two blocks move together until the friction is equal to limiting friction. The maximum acceleration of the system is given by
amax=f/m1=um1g/m2
Therefore the maximum force required to make the blocks move together is given by
Fmax=(m1+m2)um1g/m2
Fmax=(m1/m2+m2/m2)um1g
Fmax=um1g(m1/m2+1)
i.e the max force required to push the upper block so that the both the blocks move together.
Now,
case-2
If the upper block is pulled the lower block is accelerated by the frictional force between the blocks. The acceleration of the lower block is
a1=f/m1 (f is frictional force)
The two blocks move together until the friction is equal to limiting friction. The maximum acceleration of the system is given by
amax=f/m1=um1g/m2
Therefore the maximum force required to make the blocks move together is given by
Fmax=(m1+m2)um1g/m2
Fmax=(m1/m2+m2/m2)um1g
Fmax=um1g(m1/m2+1)
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sorry but the correct option is 3
but i can't calculate it
sorry for that but now check the answer
okk
thank-you thats correct
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