Question

Please someone can give me a idea to solve the questions a), and b). Thanks

Answer 1

1) It is given that 6 inches represent 72 miles in actual distance 
  Then for 1 inch it shows  72/6 = 12 miles
  Therefore the scale = 1 inch = 12miles
  Simply    6:72 = 1:x
  6x = 72
  x= 72/6 = 12
  Therefore scale  = 1 inch = 12miles
2) Distance of foston from liberty on map = 4 inch
given that total distance from liberty to west quail = 6 inch 
From the distance from liberty to west quall  subtract the distance of liberty to foston then you will get the remaining distance i.e 2 inches = 2 × 12 = 24 miles
Simply   let liberty be A foston be C and west quall be B 
AB = AC +CB
6 = 4 + CB
6-4 = CB 
2 = CB
Therefore te distance between foston and west quall = 2 × 12 = 24 miles

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