Please someone help me with my question
Coordinate of vertices of a parallelogram ABCD are A(-4,-4) , B(3,1) and C(6,2).Find the coordinate of fourth vertex of parallelogram???
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answer (-1,-3) AC= BD let D= (x,y)
(-4+6/2) + (-4+2/2)= (3+x/2)+(1+y/2)
3+x/2=1
x= 2-3
x= -1
1+y/2= -1
y= -2-1
y= -3
so therefore the fourth vertex D= (-1,-3)
Thank you
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