please someone solve it .
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(a) 0
(b) 0
(c) E.ds = q / €
E = q/A× €
• •
• q/A = sigma ( charge density)
E = sigma /€
sigma = 17× 10^-22
€ = 8.85 × 10^-12..
now solve it buddy.
in (a) and (b) electric field is 0. because both have opposite charge density.
and it will be cancel out.
hope it helps ..
tomy81:
thnx
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