Math, asked by arminsofi2, 1 year ago

Please someone solve this ​

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Answered by CHAMPION1O
1

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Answered by spacelover123
3

Let's solve your equation step-by-step.

\dfrac{9x+5}{14}+\dfrac{8x-7}{7}=\dfrac{18x+11}{28}+\dfrac{5}{4}

Step 1: Simplify both sides of the equation.

\dfrac{9x+5}{14}+\dfrac{8x-7}{7}=\dfrac{18x+11}{28}+\dfrac{5}{4}

(Distribute)

\dfrac{9}{14}x+ \dfrac{5}{14}+\dfrac{8}{7}x+-1= \dfrac{9}{14}x+\dfrac{11}{28}+ \dfrac{5}{4}

(Combine Like Terms)

(\dfrac{9}{14}x+\dfrac{8}{7}x)+ (\dfrac{5}{14}+-1)= (\dfrac{9}{14}x)+(\dfrac{11}{28}+ \dfrac{5}{4})

\dfrac{25}{14}x+\dfrac{-9}{14}=\dfrac{9}{14}x+\dfrac{23}{14}

Step 2: Subtract \bf \frac{9}{14}x from both sides.

\dfrac{25}{14}x+\dfrac{-9}{14}-\dfrac{9}{14}x=\dfrac{9}{14}x+\dfrac{23}{14}-\dfrac{9}{14}x

\dfrac{8}{7}x+ \dfrac{-9}{14}=\dfrac{23}{14}

Step 3: Add \bf \frac{9}{14} to both sides.

\dfrac{8}{7}x+ \dfrac{-9}{14}+\dfrac{9}{14}=\dfrac{23}{14}+\dfrac{9}{14}

\dfrac{8}{7}x  = \dfrac{16}{7}

Step 4: Multiply both sides by \bf  \frac{7}{8}.

\dfrac{7}{8} \times \dfrac{8}{7}x  =\dfrac{7}{8} \times  \dfrac{16}{7}

x=2

Verification if x = 2

\dfrac{9x+5}{14}+\dfrac{8x-7}{7}=\dfrac{18x+11}{28}+\dfrac{5}{4}

\dfrac{(9\times 2 )+5}{14}+\dfrac{(8\times 2) -7}{7}=\dfrac{(18\times 2) +11}{28}+\dfrac{5}{4}

\dfrac{18+5}{14}+\dfrac{16 -7}{7}=\dfrac{36 +11}{28}+\dfrac{5}{4}

\dfrac{23}{14}+\dfrac{9}{7}=\dfrac{47}{28}+\dfrac{5}{4}

\dfrac{23}{14}+\dfrac{9\times 2 }{7\times 2 }=\dfrac{47}{28}+\dfrac{5\times 7 }{4\times 7 }

\dfrac{23}{14}+\dfrac{18 }{14 }=\dfrac{47}{28}+\dfrac{35 }{28 }

\dfrac{41}{14}=\dfrac{82}{28}

\dfrac{41}{14}=\dfrac{82\div 2 }{28\div 2 }

\dfrac{41}{14}=\dfrac{41}{14}

\sf \bf \therefore x = 2 \ in \ the \ equation \rightarrow  \dfrac{9x+5}{14}+\dfrac{8x-7}{7}=\dfrac{18x+11}{28}+\dfrac{5}{4}

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